a) ${}^{20}\!\!\diagup\!\!{}_{28}\;$
b) ${}^{31}\!\!\diagup\!\!{}_{42}\;$
c) ${}^{40}\!\!\diagup\!\!{}_{54}\;$
$\frac{5}{14}+\frac{8}{21}=\frac{5}{7\times
2}+\frac{8}{7\times 3}=\frac{5\times 3}{7\times 2\times 3}+\frac{8\times
2}{7\times 3\times 2}=$
$=\frac{15}{42}+\frac{16}{42}=\frac{15+16}{42}=\frac{31}{42}$
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